Find the area of the shaded region in given figure, where $A B C D$ is a square of side $28 c m .$ [Take π = 22/7]

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Solution

Area of square $= s i d e^{2} = 28^{2} = 784 c m^{2} .$
Area of 4 circles $= 4 \times π r^{2} = 4 \times \frac{22}{7} \times (7 \times 7)$ = $616 c m^{2} .$
So,
Area of shaded region = Area of the square - area of four circles $= (784 - 616) c m^{2} = 168 c m^{2} .$

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Find the area of the shaded region in given figure, where ABCD is a square of side 28 cm. [Take π = 22/7]

Area of square =side2=282=784 cm2. Area of 4 circles =4×πr2=4×227×(7×7) = 616 cm2. So, Area of shaded region = Area of the square - area of four circles =(784−616) cm2=168 cm2.

Find the area of the shaded region in given figure, where $A B C D$ is a square of side $28 c m .$ [Take π = 22/7]

Area of square $= s i d e^{2} = 28^{2} = 784 c m^{2} .$
Area of 4 circles $= 4 \times π r^{2} = 4 \times \frac{22}{7} \times (7 \times 7)$ = $616 c m^{2} .$
So,
Area of shaded region = Area of the square - area of four circles $= (784 - 616) c m^{2} = 168 c m^{2} .$