Find the area of the shaded region in the following figure where $P Q R S$ is a rectangle $30 c m$ long and the two circles have the same radii. ( $π = 3.14$ )

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Solution

We have
$4 r = 30$
$∴2r=15(widthoftherectangle)Now,Areaofractangle=length×width=15×30=450cm2Now,Areaofshadedregion=areaofrectangle−2×areaofcircle=450−2×π×(152)2=450−2π×2254=450−3.14×2252=96.75cm2$

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Find the area of the shaded region in the following figure where PQRS is a rectangle 30 cm long and the two circles have the same radii. (π=3.14)

We have4r=30∴2r=15(widthoftherectangle)Now,Areaofractangle=length×width=15×30=450cm2Now,Areaofshadedregion=areaofrectangle−2×areaofcircle=450−2×π×(152)2=450−2π×2254=450−3.14×2252=96.75cm2

Find the area of the shaded region in the following figure where $P Q R S$ is a rectangle $30 c m$ long and the two circles have the same radii. ( $π = 3.14$ )

We have
$4 r = 30$
$∴2r=15(widthoftherectangle)Now,Areaofractangle=length×width=15×30=450cm2Now,Areaofshadedregion=areaofrectangle−2×areaofcircle=450−2×π×(152)2=450−2π×2254=450−3.14×2252=96.75cm2$