CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Find the area of the shaded region in the given figure, where a circular arc of radius 6 cm has been drawn with vertex of an equilateral triangle of side 12 cm as centre and a sector of circle of radius 6 cm with centre B is made. [ Use 3=1.73andπ=3.14.]


Solution

OAB is an equilateral triangle with each angle equal to 60o.

Area of the sector is common in both.

Radius of the circle = 6 cm.

Side of the triangle = 12 cm.

Area of the equilateral triangle =34×(OA)2=34×122=363 cm2

Area of the circle =πR2=227×62=7927 cm2

Area of the sector making angle 60o=60o360o×πr2 cm2=16×227×62 cm2=1327 cm2

Area of the shaded region = Area of the equilateral triangle + Area of the circle - Area of the sector

=363 cm2+7927 cm21327 cm2=(363+6607) cm2=62.28+94.2857143=156.56 cm2


Mathematics
Secondary School Mathematics X
Standard X

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
Same exercise questions
View More


similar_icon
People also searched for
View More



footer-image