Find the area of the smaller part of the circle x² + y² = a² cut off by the line

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Solution

The area of the smaller part of the circle, x² + y² = a², cut off by the line, , is the area ABCDA.

It can be observed that the area ABCD is symmetrical about x-axis.

∴ Area ABCD = 2 × Area ABC

Therefore, the area of smaller part of the circle, x² + y² = a², cut off by the line, , is units.

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Similar questions

Find the area of the smaller part of the circle $x^{2} + y^{2} = a^{2}$ cut-off by the line $x = \frac{a}{\sqrt{2}} .$

x^{2} + y^{2} = a^{2}

x = \frac{a}{\sqrt{2}}

x^{2} + y^{2} = 4

x = 1

x^{2} + y^{2} = a^{2}

x = \frac{a}{\sqrt{2}}

\frac{a^{2}}{2} (\frac{π}{P} - 1)

P

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