Question

Find the area of the square built upon BC when 7 sq. units is the area of those squares labelled.

• A. $7$
• B. $7\sqrt{2}$
• C. $14$
• D. $14\sqrt{2}$

Answer 1

The correct option is C $14$

In a right-angled triangle, square of the largest side is equal to the sum of the squares of the other 2 sides.

Area of the square upon AC = 7
Area = (Side)${}^2$
Side = Square root of area
AC $=\sqrt{7}unit$

Area of the square upon AB = 7
Area = (Side)${}^2$
Side = Square root of area
AB $=\sqrt{7}unit$

Area of the square upon BC $=B{C}^2$
$B{C}^2=A{B}^2+A{C}^2$
Area of the square upon BC$=(\sqrt{7}{)}^2+(\sqrt{7}{)}^2=7+7=14sq.units$