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Question

Find the area of the trapezium ABCD in which AB//DC, AB =18 cm, B=C=90,CD=12 cm and AD =10 cm.


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Solution

In trapezium ABCD,

AB||DC, AB=18 cm

B=C=90, CD =12 cm and AD =10 cm

Area of trapezium ABCD

Draw DLAB

AL=1812=6cm

AL =BC

AL=AD2AL2

=10262=10036

=64=8cm

Now area of trapezium =12(AB+CD)×AL

=12(18+12)×8cm2

=12×30×8=120cm2


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