Find the area of the trapezium whose parallel sides are 14 cm and 10 cm and whose height is 6 cm.

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Solution

Area of the trapezium = $\frac{1}{2}$ × (sum of the parallel sides) × (distance between them)
= $\frac{1}{2}$ × ( 14 + 10) × 6
= 72 cm²
∴ The area of the trapezium is 72 cm².

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Find the area of the trapezium whose parallel sides are 14 cm and 10 cm and whose height is 6 cm.

Area of the trapezium = 12 × (sum of the parallel sides) × (distance between them) = 12× ( 14 + 10) ​× 6 = 72 cm2 ∴ The area of the trapezium is 72 cm2.

Area of the trapezium = $\frac{1}{2}$ × (sum of the parallel sides) × (distance between them)
= $\frac{1}{2}$ × ( 14 + 10) × 6
= 72 cm²
∴ The area of the trapezium is 72 cm².