Question

Find the area of the triangle formed by the lines joining the vertex of the parabola $x^2=12y$ to the ends of its latus rectum.

Answer 1

The given equation of the parabola is x² = 12y.

On comparing the given equation with $x^2=4ay$:
a = 3



Required area = $\frac{1}{2}\left(LL\text{'}\times OS\right)=\frac{1}{2}\times 12\times 3=18\mathrm{square}\mathrm{units}$