Question

Find the area of the triangle(in $c{m}^2$) with base $6cm$ and height $4cm$

Answer 1

Here, In $△ABC,$ $BC$ and $AD$ are base and height of triangle.

$\therefore$ $BC=6cm$ and $AD=4cm$

$\Rightarrow$ Area of $△ABC=\frac{1}{2}\times BC\times AD$

$=\frac{1}{2}\times 6\times 4$

$=3\times 4$

$=12c{m}^2$