Find the area of the triangle which the line 2x - 3y + 6 = 0 forms with the coordinate axis

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Solution

The correct option is A 3
$2 y + 3 x - 6 = 0$ has an $x$ intercept of $2$ and a $y$ intercept of $3$ .
That means the $2$ sides of the right triangle are $2$ and $3$
Area of triangle= $\frac{1}{2} \times b a s e \times h e i g h t$
= $\frac{1}{2} \times 3 \times 2$
= $3$
$∴$ Area of the triangle= $3$

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Find the area of the triangle which the line 2x - 3y + 6 = 0 forms with the coordinate axis

The correct option is A 32y+3x−6=0 has an x intercept of 2 and ay intercept of 3. That means the 2 sides of the right triangle are 2 and 3Area of triangle=12×base×height =12×3×2 =3∴ Area of the triangle=3