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Byju's Answer
Standard IX
Mathematics
Area of a Triangle - by Heron's Formula
find the area...
Question
find the area of the triangle whose are (-5,-1) (3,-5) (5,2).
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Solution
Points:
(
−
5
,
−
1
)
(
,
−
5
)
(
5
,
2
)
x
1
=
5
,
y
1
=
−
1
,
x
2
=
3
,
y
2
=
−
5
,
x
3
=
5
,
y
3
=
2
Area of the triangle
=
1
2
[
x
,
(
y
2
−
y
3
)
+
x
2
(
y
3
−
y
1
)
)
+
x
3
(
y
1
−
y
)
]
=
1
2
[
−
5
(
−
5
−
2
)
+
3
(
2
−
(
−
1
)
)
+
5
(
−
1
(
−
5
)
)
]
=
1
2
[
−
5
(
−
7
)
+
3
(
3
)
+
5
(
−
1
+
5
)
]
=
1
2
[
35
+
9
+
5
+
(
4
)
]
=
1
2
[
35
+
9
+
20
]
=
1
2
[
35
+
29
]
⇒
1
2
[
64
]
=
32
The area of triangle is =
32
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Similar questions
Q.
Find the area of the triangle whose vertices are (-5,-1)(3,-5)(5,2)
Q.
Question 1 (ii)
Find the area of the triangle whose vertices are:
(ii) (-5, -1), (3, -5), (5, 2)
Q.
Find the area of
△
le with coordinate of vertices
A
(
−
5
,
−
1
)
,
B
(
3
,
−
5
)
and
C
(
5
,
2
)
resp. Find the length of median trough
B
.
Q.
Given three vertices of a triangle whose coordinates are A (1, 1), B (3, -3) and (5, -3). Find the area of the triangle.
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