Question

Find the area of the triangle whose sides are along the lines $x=3,y=0$ and $4x+5y=20$

Answer 1

We have,

$x=3,$

$y=0,$

$4x+5y=20$

First put$x=3$ so,

$4\times 3+5y=20$

$\Rightarrow 5y=20-12$

$\Rightarrow 5y=8$

$\Rightarrow y=\frac{8}{5}$

Now, put$y=0$ so,

$4x+5\times 0=20$

$\Rightarrow x=5$

Now,

Area of the triangle

$=\frac{1}{2}\times 5\times \frac{8}{5}$

$=4uni{t}^2$

Hence, this is the answer.