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Question

Find the area of the triangle whose vertices are (3,2), (−2,−3) and (2,3).

A
8 sq.unit
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B
7 sq.unit
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C
6 sq.unit
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D
5 sq.unit
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Solution

The correct option is D 5 sq.unit
Area of a triangle with vertices (x1,y1); (x2,y2) and (x3,y3)
=x1(y2y3)+x2(y3y1)+x3(y1y2)2

Hence, substituting the points (x1,y1)=(3,2) ; (x2,y2)=(2,3) and (x3,y3)=(2,3)
in the area formula, we get

Area = 3(33)+(2)(32)+2(2(3))2=5 sq. unit

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