Find the area of the triangle whose vertices are $(10, - 6), (2, 5)$ and $(- 1, 3)$ .

Open in App

Solution

$(10, - 6); (2, 5); (- 1, 3)$
$x_{1} y_{1}$ $x_{2} y_{2}$ $x_{3} y_{3}$
$= A r e a = \frac{1}{2} | x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2}) |$
$= \frac{1}{2} | 10 (5 - 3) + 2 (3 + 6) - 1 (- 6 - 5) |$
$= \frac{1}{2} | 10 (2) + 2 (9) - 1 (- 11) |$
$= \frac{1}{2} | 20 + 18 + 11 |$
$= \frac{1}{2} | 49 |$
$= 24.5$

Suggest Corrections

Similar questions

Using integration find the area of region bounded by the triangle whose vertices are (-1, 0),(1, 3) and (3, 2).

(1, 3), (2, 7)

(12, - 16) .

Find the coordinates of the orthocentre of the triangle whose vertices are $(- 1, 3), (2, - 1)$ and $(0, 0)$ .

Join BYJU'S Learning Program