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Question

Find the area of the triangle with coordinates A(-2, 1), B(3, 3) and C(1, -2).


A

10 sq. units

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B

10.5 sq. units

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C

11 sq. units

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D

11.5 sq. units

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Solution

The correct option is B

10.5 sq. units


Area of a triangle having vertices (x1,y1),(x2,y2) and (x3,y3)
=12[x1(y2y3)+x2(y3y1)+x3(y1(y2)]

Given, (x1,y1) = (-2, 1)

(x2,y2) = (3, 3)

(x3,y3) = (1, -2)

=12[2(3+2)+3(21)+1(13)]=10.5

Since area is not a negative quantity, take the absolute value.

Thus, area of the given triangle = 10.5 sq. units.


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