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Byju's Answer
Standard X
Mathematics
Area of a Triangle Given Its Vertices
Find the area...
Question
Find the area of the triangles (in sq. units) formed by the points
(
−
2
,
3
)
,
(
7
,
5
)
and
(
3
,
−
5
)
.
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Solution
Area of the triangle
=
1
2
×
|
x
1
(
y
2
−
y
3
)
+
x
2
(
y
3
−
y
1
)
+
x
3
(
y
1
−
y
2
)
|
=
1
2
×
|
−
2
(
5
−
(
−
5
)
)
+
7
(
−
5
−
3
)
+
3
(
3
−
5
)
|
=
1
2
×
|
(
−
20
)
+
(
−
56
)
+
(
−
6
)
|
=
1
2
×
|
−
82
|
=
41
square units.
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The area (in sq. units) of the triangle formed by the points
(
−
3
,
0
)
,
(
1
,
−
3
)
and
(
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,
1
)
is
Q.
Let ABC be a triangle of area 24 sq. units and PQR be the triangle formed by the mid-points of the sides of Δ ABC. Then the area of ΔPQR is
(a) 12 sq. units
(b) 6 sq. units
(c) 4 sq. units
(d) 3 sq. units