Question

Find the area of the unshaded part of the given figure

• A. $45sq.cm$
• B. $52sq.cm$
• C. $68sq.cm$
• D. $78sq.cm$

Answer 1

The correct option is C $68sq.cm$

$\Rightarrow$ In given figure, ABCD is a rectangle with $l=12cm$ and $b=8cm.$.

$\therefore$ Area of rectangle ABCD = $l\times b=12\times 8=96c{m}^2$

$\Rightarrow$ AMNO is also a rectangle, with $l=6cm$ and $b=2cm.$

$\therefore$ Area of a rectangle AMNO = $l\times b=6\times 2=12c{m}^2$

$\Rightarrow$ In figure, PQRS is a square with $s=4cm.$

$\therefore$ Area of square PQRS = $s^2=4^2=16c{m}^2$

$\Rightarrow$ The area of the unshaded part = Area of a rectangle ABCD - (Area of rectangle AMNO + Area of a square PQRS)

$\therefore$ The area of the unshaded part = $96-(12+16)$

$\therefore$ The area of the unshaded part = $96-28$

$\therefore$ The area of the unshaded part = $68c{m}^2$