Question

Find the area of trapezium $ABCD$ as given in the figure in which $ADCE$ is a rectangle.

Answer 1

Given :

BE= 3 cm , EA = 3cm and AD = 8cm

Area of trapezium (ABCD) $=\frac{1}{2}\times$ sum of parallel sides $\times$ height.

$\Rightarrow$ Area of trapezium ABCD $=\frac{1}{2}\times (AB+CD)\times AD$

$\Rightarrow$Area of trapezium ABCD$=\frac{1}{2}\times (6+3)\times 8$

$\Rightarrow$ Area of trapezium ABCD$=\frac{1}{2}\times 9\times 8$

$\Rightarrow$Area of trapezium ABCD $=36$ $m^2$