Question

Find the area of triangle of sides $6cm,8cm,10cm$

• A. $24c{m}^2$
• B. $12c{m}^2$
• C. $30c{m}^2$
• D. $none$

Answer 1

The correct option is A $24c{m}^2$

The sides are $6cm,8cm,10cm$

$s=\frac{6+8+10}{2}=\frac{24}{2}=12$

The area is given as $\sqrt{s(s-a)(s-b)(s-c)}\sqrt{12\left(6\right)\left(4\right)\left(2\right)}\sqrt{576}=24c{m}^2$