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Byju's Answer
Standard XII
Mathematics
Determinant
Find the area...
Question
Find the area of
△
P
Q
R
whose vertices are
P
(
2
,
1
)
,
Q
(
3
,
4
)
and
R
(
5
,
2
)
.
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Solution
Area of
Δ
=
1
2
∣
∣ ∣
∣
1
1
1
2
3
5
1
4
2
∣
∣ ∣
∣
=
1
2
[
(
6
−
10
)
+
(
5
−
4
)
+
(
8
−
3
)
]
=
1
2
[
−
4
+
1
+
5
]
=
1
sq.units.
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1
Similar questions
Q.
Find the area of
Δ
PQR whose vertices are
P
(
2
,
1
)
,
Q
(
3
,
4
)
and
R
(
5
,
2
)
.
Q.
P
(
2
,
1
)
,
Q
(
2
,
5
)
and
R
(
k
,
5
)
are the three vertices of
△
P
Q
R
in which
∠
Q
=
90
o
. If the area of
△
P
Q
R
is
10
u
n
i
t
2
, the value of
k
is:
Q.
The vertices of
△
P
Q
R
are
P
(
2
,
1
)
,
Q
(
−
2
,
3
)
and
R
(
4
,
5
)
. Find equation of the median through the vertex
R
.
Q.
Using integration, find the area of the triangle
P
Q
R
, whose vertices are
P
(
2
,
5
)
,
Q
(
4
,
7
)
and
R
(
6
,
2
)
.
Q.
If the points
P
(
2
,
1
,
−
3
)
,
Q
(
5
,
4
,
3
)
and
R
(
1
,
4
,
7
)
are three vertices of a parallelogram
P
Q
R
S
then the other vertex is
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