Question

Find the area of triangle two sides of which are $16cm$ and $22cm$ and perimeter is $64cm$.

Answer 1

Let sides be a, b, c

$a=16$ cm

$b=22$ cm

Perimeter$=64$

$a+b+c=64$

$16+22+c=64$

$C=26$

$S=\left(\frac{64}{2}\right)=32$

Area, $\Delta =\sqrt{s(s-a)(s-b)(s-c)}$

$\Delta =\sqrt{32(32-16)(32-22)(32-26)}$

$\Delta =32\sqrt{30}c{m}^2$.