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Modulus of a Complex Number

Find the argu...

Question

Find the argument of $i^{i}$ .

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Solution

$z = i^{i} = e^{(i π / 2) i} = e^{- π / 2}$ $[∵ i = e^{i π / 2}]$
$∴ A r g (z) = A r g (i^{i}) = 0$

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