Find the arithmetic mean using the assumed-mean method:
Class interval 100-120 120-140 140-160 160-180 180-200
Frequency 10 20 30 15 5

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Solution

Let mean $= 150$
$\Rightarrow A = 150$
$\Rightarrow$ Mean $= A + \frac{\sum f d}{\sum f}$
$= 150 + \frac{(- 30 ϕ)}{8 ϕ} = 150 - \frac{15}{4} = 150 - 3.75$
$= 146.25$ .

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Q. Consider the following distribution of daily wages of

50

workers of a factory.

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Number of workers	12	14	8	6	10

Find the mean daily wages of the workers of the factory by using an appropriate method.

Question 2
Consider the following distribution of daily wages of 50 worker of a factory.

$\begin{matrix} Daily wages (in Rs) & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 Number of workers & 12 & 14 & 8 & 6 & 10 \end{matrix}$

Find the mean daily wages of the workers of the factory by using an appropriate method.

Q. The following table gives the daily income of 50 workers of a factory :

Daily income (in ₹) 100-120 120-140 140-160 160-180 180-200

Number of workers : 12 14 8 6 10

Find the mean, mode and median of the above data .

Find the mean of the following data using assume mean method :

Class 0-10 ; F 8

Class 10-20 ; F 12

Class 20-30 ; F 10

Class 30-40 ; F 6

Class interval	$10 - 15$	$15 - 20$	$20 - 25$	$25 - 30$
Frequency	$7$	$12$	$8$	$10$

Find the mean of the following data using Assumed mean method.

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Find the arithmetic mean using the assumed-mean method:Class interval100-120120-140140-160160-180180-200Frequency 10 20 30 15 5

Let mean=150⇒A=150⇒ Mean=A+∑fd∑f=150+(−30ϕ)8ϕ=150−154=150−3.75=146.25.

Find the arithmetic mean using the assumed-mean method:
Class interval 100-120 120-140 140-160 160-180 180-200
Frequency 10 20 30 15 5

Let mean $= 150$
$\Rightarrow A = 150$
$\Rightarrow$ Mean $= A + \frac{\sum f d}{\sum f}$
$= 150 + \frac{(- 30 ϕ)}{8 ϕ} = 150 - \frac{15}{4} = 150 - 3.75$
$= 146.25$ .