Question

Find the average angular speed of the minute hand of a normal clock in $30\text{minutes}$.

• A. $\frac{\pi }{900}rad/s$
• B. $\frac{\pi }{1800}rad/s$
• C. $\frac{1800}{\pi }rad/s$
• D. $1800rad/s$

Answer 1

The correct option is B $\frac{\pi }{1800}rad/s$

We know that the average angular speed is given by,
$\overline{\omega }=\frac{\text{Total angular displacement}}{\text{Time taken}}$

$\Rightarrow \overline{\omega }=\frac{\pi }{30\times 60}=\frac{\pi }{1800}\text{rad/s}$