Question

Find the average current for the time interval $t=0$ to $t=5\text{s}$ if the current is given by, $i=(2t+1)\text{A}$.

• A. $2\text{A}$
• B. $4\text{A}$
• C. $6\text{A}$
• D. $8\text{A}$

Answer 1

The correct option is C $6\text{A}$

Average current is given by,

$i_{avg}=\frac{{\int }_{t_1}^{t_2}idt}{{\int }_{t_1}^{t_2}dt}$

$\Rightarrow i_{avg}=\frac{{\int }_0^5(2t+1)dt}{{\int }_0^{5}dt}$

$\Rightarrow i_{avg}=\frac{[t^2+t{]}_0^5}{[t{]}_0^5}=6\text{A}$