The acceleration of the car is given as,
v2=u2+2as
(72×518)2=0+2×a×25
a=8m/s2
The force is given as,
F=ma
=500×8
=4000N
Thus, the average force needed to accelerate the car is 4000N.
Find the average frictional force needed to stop a car weighing 500 kg in a distance of 25 m if the initial speed is 72 km/h.