Find the average marks secured by Anju. Will you divide the total marks by $3$ or $4$ ? Why?

19

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20

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21

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23

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Solution

The correct option is C $21$
We know that,
$A v e r a g e = \frac{S u m o f a l l o b s e r v a t i o n s}{N u m b e r o f o b s e r v a t i o n s}$

Average marks obtained by Anju $= \frac{19 + 23 + 21}{3} = \frac{63}{3} = 21$ Marks

We will divide the total marks by $3$ because in one test he is Absent.

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Similar questions

Given below are marks obtained by $20$ students in Math out of $25$ .

$21, 23, 19, 17, 12, 15, 15, 17, 17, 19, 23, 23, 21, 23, 25, 25, 21, 19, 19, 19$

Prepare a frequency distribution table for the given data.

The marks obtained in physics by 10 students are:-
23, 19, 22, 25, 23, 17, 21, 23, 20, 14
What is the mode of the given data?

12

%

600

15

%

800

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