Question

Find the average value of current (in A) as shown graphically in the figure, from $t=0$ to $t=2s$.

Answer 1

We know,
$⟨i{⟩}_{avg}=\frac{\int idt}{\int dt}$
$\frac{\int idt}{\int dt}=\frac{10}{2}=5$
Since, $\int idt$ is area under the graph.