Find the axis of symmetry of the graph $f (x) = - 0.5 x^{2} + 1.1 x - 2.3$

x = 0

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x = 1

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x = 1.1

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x = - 0.5

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Solution

The correct option is D $x = 1.1$
For a quadratic function in standard form $a x^{2} + b x + c$ .
The axis of symmetry is a vertical line $x = - \frac{b}{2 a}$ .
Therefore, the axis of symmetry of the function $f (x) = - 0.5 x^{2} + 1.1 x - 2.3$ is given by:
$x = - \frac{b}{2 a} = - \frac{(1.1)}{2 (- 0.5)} = - \frac{1.1}{- 1} = 1.1$

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