Find the axis of symmetry of the graph of $f (d) = - 2 x^{2} - x - 2$

\frac{- 1}{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{- 1}{4}$
For a quadratic function in standard form $a x^{2} + b x + c$ , the axis of symmetry is a vertical line $x = - \frac{b}{2 a}$ .
Therefore, the axis of symmetry of the function $f (x) = - 2 x^{2} - x - 2$ is given by:
$x = - \frac{b}{2 a} = - \frac{(- 1)}{2 (- 2)} = \frac{1}{- 4} = - \frac{1}{4}$

Suggest Corrections

Similar questions

y = 3 x^{2} + 6 x - 1

\frac{{(x - 1)}^{2}}{9} + \frac{{(y + 2)}^{2}}{16} = 1

2 c m = 1

x

y

O (0, 0), A (- 4, 4), B (- 3, 0)

C (0, - 3)

f

2

x = - 3

f (2) = 1

\frac{1}{4} [\frac{1}{\sqrt{2 x^{2} + 5}} - \frac{1}{\sqrt{2 x^{2} - 3}}]

Join BYJU'S Learning Program