Find the binding energy of a body of mass $50$ kg at rest on the surface of the earth.
given $G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}$
$R = 6400 k m, M = 6 \times 10^{24} k g$

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Solution

Binding energy=-potential energy
$B i n d i n g e n e r g y = - (- \frac{G M m}{R}) = \frac{G M m}{R}$
$B i n d i n g e n e r g y = \frac{6.67 \times 10^{- 11} \times 6 \times 10^{24} \times 50}{6400 \times 10^{3}} J = 3.126 \times 10^{9} J$

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