You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Reasons of Stability

Find the bind...

Question

Find the binding energy of an $α -$ particle from the following data.
Mass of the helium nucleus $= 4.001265 a m u$
Mass of proton $= 1.007277 a m u$
Mass of neutron $= 1.00866 a m u$
(take $1 a m u = 931.4813 M e V)$

Open in App

Solution

The alpha particle has two proton and two neutron.
The combined mass of nuclei $=$ net mass of proton $+$ net mass of neutron $= (2 \times 1.007277) + (2 \times 1.00866) = 4.031874$ amu
Binding energy $=$ mass defect $= 4.031874 - 4.001265 = 0.0306 a m u = 0.0306 (931.48) = 28.5 M e V$

Suggest Corrections

Similar questions

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

Q. What is meant by binding energy of nucleus? Determine the binding energy per nucleon of an

α

particle if the masses of proton, neutron and

α

- particle are

1.00728 a m u

1.00867 a m u

and

4.00150 a m u

respectively.
(Given:

1 a m u = 931 M e V

)

Q. What would be the energy required to dissociate completely

1 g

C a^{40}

into its constituent particles?
Given: Mass of proton

= 1.007277 a m u

,
Mass of neutron

= 1.00866 a m u

,
Mass of

C a - 40 = 39.97545 a m u

(Take

1 a m u = 931 M e V)

Q. Calculate the mass defect and binding energy per nucleon of

_{8}^{16} O

which has a mass

15.99491 a m u

.
Mass of neutron

= 1.008655 a m u

Mass of proton

= 1.007277 a m u

Mass of electron

= 0.0005486 a m u

1 a m u = 931.5 M e V

Q. The masses of neutron and proton are

1.0087 a . m . u .

and

1.0073 a . m . u .

respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass

4.0015 a . m . u

, then the binding energy fo the helium nucleus will be: (

1 a . m . u . = 931 M e V

)

Join BYJU'S Learning Program

Find the binding energy of an α− particle from the following data.Mass of the helium nucleus =4.001265amuMass of proton =1.007277amuMass of neutron =1.00866amu(take 1amu=931.4813MeV)

The alpha particle has two proton and two neutron. The combined mass of nuclei =net mass of proton + net mass of neutron =(2×1.007277)+(2×1.00866)=4.031874 amuBinding energy = mass defect =4.031874−4.001265=0.0306amu=0.0306(931.48)=28.5MeV

Find the binding energy of an $α -$ particle from the following data.
Mass of the helium nucleus $= 4.001265 a m u$
Mass of proton $= 1.007277 a m u$
Mass of neutron $= 1.00866 a m u$
(take $1 a m u = 931.4813 M e V)$

The alpha particle has two proton and two neutron.
The combined mass of nuclei $=$ net mass of proton $+$ net mass of neutron $= (2 \times 1.007277) + (2 \times 1.00866) = 4.031874$ amu
Binding energy $=$ mass defect $= 4.031874 - 4.001265 = 0.0306 a m u = 0.0306 (931.48) = 28.5 M e V$