Find the binding energy per nucleon of $_{79}^{197} A u$ if its atomic mass is 196.96 u. The atomic mass of $_{1}^{1} H$ is 1.007825 u, mass of neuton, $m_{n} = 1.008665 u, m_{p} = 1.007276 u . c^{2} = 931 \frac{M e V}{u} .$
Remember that atomic mass also contains the mass of electrons.

Q. Find the binding energy of

_{26}^{56} F e

. Atomic mass of

^{56} F e

is 55.9349 u and that of

^{1} H

is 1.00783 u. Mass of neutron = 1.00867 u.

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Find the binding energy per nucleon for 12050Sn. Mass of proton mp=1.00783 U, mass of neutron mn=1.00867 U and mass of tin nucleus mSn=119.902199 U. (take 1 U=931 MeV)

The correct option is D 8.5 MeVMass defect Δm=(50 mp+70 mn)−(msn) =(50×1.00783+70×1.00867)–(119.902199) =1.0962 U Binding energy =(Δm)C2=(Δm)×931=1020.56 MeV Binding energyNucleon=1020.5631120=8.5 MeV. Hence, (D) is the correct answer.

Find the binding energy per nucleon for $_{50}^{120} S n$ . Mass of proton $m_{p} = 1.00783 U$ , mass of neutron $m_{n} = 1.00867 U$ and mass of tin nucleus $m_{S n} = 119.902199 U$ . (take $1 U = 931 MeV)$