Question

Find the binding energy per nucleon of ${}_{79}^{197}$Au if its atomic mass is 196.96 u.

Answer 1

Given,

B = ($Z{m}_p+N{m}_n-M)c^2$

Z = 79; N = 118

$m_p=1.007276u$

M = $196.96u$

$m_n$ = 1.008665 u

$B=\left[\right(79\times 1.007276+118\times 1.008665)u-Mu]c^2$

$=198.597274\times 931-196.96\times 931$

=$1524.302094$

$\text{So, Binding Energy per nucleon}$

=$\frac{1524.3}{197}=7.737$