Find the breadth and the perimeter of the rectangle if its area is 96 cm $^{2}$ and the length is 12 cm.

10 cm, 40 cm

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12 cm, 42 cm

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8 cm, 40 cm

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12 cm, 40 cm

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Solution

The correct option is C
8 cm, 40 cm

Given, A = 96 cm $^{2}$ and l = 12 cm

A = l $\times$ b

Therefore, 96 = 12 $\times$ b

$\Rightarrow \frac{96}{12}$ = b

$\Rightarrow$ b = 8 cm

Now, P = 2 $\times$ (l + b)

= 2 $\times$ (12 + 8)

= 2 $\times$ 20

= 40 cm

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The perimeter of a rectangle is 40 cms. Can you find the length of the rectangle if its breadth 8 cms?

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Find the breadth and the perimeter of the rectangle if its area is 96 cm2 and the length is 12 cm.

The correct option is C 8 cm, 40 cm Given, A = 96 cm2and l = 12 cm A = l × b Therefore, 96 = 12 × b ⇒9612= b ⇒​ b = 8 cm Now, P = 2 × (l + b) = 2 × (12 + 8) = 2 × 20 = 40 cm

Find the breadth and the perimeter of the rectangle if its area is 96 cm $^{2}$ and the length is 12 cm.

The correct option is C
8 cm, 40 cm

Given, A = 96 cm $^{2}$ and l = 12 cm

A = l $\times$ b

Therefore, 96 = 12 $\times$ b

$\Rightarrow \frac{96}{12}$ = b

$\Rightarrow$ b = 8 cm

Now, P = 2 $\times$ (l + b)

= 2 $\times$ (12 + 8)

= 2 $\times$ 20

= 40 cm