Find the cardial number of A - B- such that A-1-2-3 and B-a- b-A- 6

The correct option is A 6Given, nbsp; A = 1, 2, 3 B = a, b A× B= (1, a), (1, b), (2, a), (2, b), (3, a), (3, b) The cardial number of nbsp;A× B=6 OR n(A) ...

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Question

Find the cardial number of $A \times B$ , such that A = {1, 2, 3} and B = {a, b}.
6

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Solution

The correct option is A 6
Given,
A = {1, 2, 3}
B = {a, b}

$A \times B =$ {(1, a), (1, b), (2, a), (2, b), (3, a),
(3, b)}
The cardial number of $A \times B = 6$

OR

$n (A) = 3, n (B) = 2$ ,
n( $A \times B) = n (A) \times n (B) = 3 \times 2 = 6$

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Find the cardial number of A×B, such that A = {1, 2, 3} and B = {a, b}.6

The correct option is A 6Given, A = {1, 2, 3} B = {a, b} A×B= {(1, a), (1, b), (2, a), (2, b), (3, a), (3, b)} The cardial number of A×B=6 OR n(A)=3,n(B)=2, n(A×B)=n(A)×n(B)=3×2=6

Find the cardial number of $A \times B$ , such that A = {1, 2, 3} and B = {a, b}.
6

The correct option is A 6
Given,
A = {1, 2, 3}
B = {a, b}

$A \times B =$ {(1, a), (1, b), (2, a), (2, b), (3, a),
(3, b)}
The cardial number of $A \times B = 6$

OR

$n (A) = 3, n (B) = 2$ ,
n( $A \times B) = n (A) \times n (B) = 3 \times 2 = 6$