Find the case where heat flow can take place in between the two bodies. Given are the temperatures of both the bodies, measured with two different scales.
A
BodyA:0°CBodyB:273K
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B
BodyA:37°CBodyB:98.6°F
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C
BodyA:100°CBodyB:212°F
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D
BodyA:10°CBodyB:212°F
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Solution
The correct option is DBodyA:10°CBodyB:212°F Heat flows from a body at a higher temperature to a region at lower temperature. When there is no difference in temperatures, no heat flow will take place. We know the following conversion of scales, F=(C×95)+32C=(F−32)×59K=C+273 Using these formulae we get, (a)0°C=273K(Meltingpointofice)(b)37°C=98.6°F(Normalbodytemperature)(c)100°C=212°F(Boilingpointofwater) but (d)10°C=50°Fsince,F=9/5(°C)+32F=9/5×10+32F=50°FSince the temperatures are not equal in this case. Heat flow happens from body B and A.