Q. Two conducting parallel plates have area
A, are separated by distance
d, and are filled with a dielectric material of constant
K1. The capacitance of this system is
C. A student plans to replace the dielectric
K1 with a second dielectric,
K2, where
K2=2K1. However, the student only has half the volume of dielectric material to fully replace
K1. So the student fills half the gap with
K1 and half with
K2. Both
K1 and
K2 have a cross sectional area of
A, but a thickness of
d/2, as shown in the diagram above.
In terms of
C, what is the new capacitance of this modified system?
