Question

Find the center and radius of the circle whose equation is given by: ${(-4-x)}^2+{(-y+11)}^2=9$

Answer 1

An equation of the circle with center $(h,k)$ and radius $r$ is

$(x-h{)}^2+(y-k{)}^2=r^2$

So, comparing $(-4-x{)}^2+(-y+11{)}^2=9$ that is $(x-(-4){)}^2+(y-11{)}^2=9$ with the above equation of circle we get:

$h=-4$, $k=11$ and $r=3$

Therefore, center of the circle is $(-4,11)$ and radius of the circle is $r=3$.