Question

Find the center and radius of the circle whose equation is given by ${(5-x)}^2+{(y-1)}^2=4$

Answer 1

An equation of the circle with center $(h,k)$ and radius $r$ is

$(x-h{)}^2+(y-k{)}^2=r^2$

So, comparing $(5-x{)}^2+(y-1{)}^2=4$ that is $(x-5{)}^2+(y-1{)}^2=4$ with the above equation of circle we get:

$h=5$, $k=1$ and $r=2$

Therefore, center of the circle is $(5,1)$ and radius of the circle is $r=2$.