Find the center and radius of the circle x $^{2}$ + y $^{2}$ + 6x - 12y + 20 = 0

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Solution

$x^{2} + y^{2} + 6 x - 12 y + 20 = 0$
$(x + 3)^{2} + (y - 6)^{2} - 9 - 36 + 20 = 0$
$(x + 3)^{2} + (y - 6)^{2} = 25$
Therefore,
Centre of circle is $O (- 3, 6)$ and radius is $5$ $u n i t s$

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