Question

Find the centre and radius of each of the following circle.
$(x-\frac{1}{2}{)}^2+(y+\frac{1}{3}{)}^2=\frac{1}{36}$

Answer 1

${(x-\frac{1}{2})}^2+{(y+\frac{1}{3})}^2=\frac{1}{36}$

${(x-\frac{1}{2})}^2+{(y+\frac{1}{2})}^2={\left(\frac{1}{6}\right)}^2$

Hence $(\frac{1}{2},\frac{1}{3})$ is the centre and $\frac{1}{6}$ is the radius of the circle