Question

Find the centre and radius of the circle: $x^2+y^2-6x-8y+24=0$

Answer 1

Given the equation of the circle is $x^2+y^2-6x-8y+24=0$

or, $(x^2-6x+9)+(y^2-8y+16)-1=0$

or, $(x-3{)}^2+(y-4{)}^2=1$

So, the centre is $(3,4)$ and radius is $1$.