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Question

Find the centre of gravity of a triangular lamina, each side of which measures [9 x root of 3]cm.

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Solution

$I n T r i a n g u l a r L a m i n a t h e c e n t r e o f g r a v i t y w i l l b e 2 / 3 r d o f i t s s i d e c o o r d i n a t e o f C e n t r e o f G r a v i t y (9 \sqrt{3} \times \frac{2}{3} . 9 \sqrt{3} \times \frac{2}{3}) (6 \sqrt{3}, 6 \sqrt{3})$

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