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Question

Find the centre of the ellipse whose equation is x2+2xy+2y2−1=0. Also, find the length of the major and minor axes.

A
Centre: (1,1)
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B
Length of major - axis =2235
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C
Length of minor - axis =223+5
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D
Centre: (0,0)
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Solution

The correct option is D Centre: (0,0)
Given: x2+2xy+2y21=0

To Find: (i) Centre of the ellipse (ii) Length of major and minor axes

Step-1: Recall the standard equation of conic

Step-2: Recall the method od partial differentiation and find the centre

Step-3: Assume parametric coordinates of any point on ellipse and find major and minor axes

(i) Centre of the ellipse

The general 2nd degree equation of a conic is ax2+2hxy+by2+2gx+2fy+c=0

The centre of this equation can be found using partial differentiation.

δf(x,y)δx=2x+2y=0

δf(x,y)δy=2x+4y=0

On solving the two equations we get x=0 and y=0

So, the centre is (0,0).

(ii) Length of major and minor axes

Let P(rcosθ,rsinθ) be any point on the given ellipse.

r= Maximum distance of point P from the centre (0,0)

(rcosθ)2+2(rsinθ)2+2rcosθ rsinθ1=0

r2cos2θ+2r2sin2θ+2r2cosθsinθ1=0

r2(cos2θ+sin2θ)+r2sin2θ+2r2cosθ sinθ1=0

r2+r2(1cos2θ2)+2r2sin2θ2=0

3r2+r2(2sin2θcos2θ)=2

r2=23+2sin2θcos2θ

Maximum length of r = Length of semi - major axis

Minimum length of r = Length of semi - minor axis

22+(1)22sin2θcos2θ22+(1)2

52sin2θcos2θ5

r2max=235 and r2min=23+5

rmax=235 and rmin=23+5

Length of major - axis =2rmax=2235

Length of minor - axis =2rmin=223+5

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