Find the centroid of a triangle, mid-points of whose sides are $(1, 2, - 3), (3, 0, 1)$ and $(- 1, 1, - 4)$ .

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Solution

$A (1, 2, 3), B (3, 0, 1)$ and $C (- 1, 1, - 4)$
Centroid $(G) = (\frac{1 + 3 + (- 1)}{3}, \frac{2 + 0 + 1}{3}, \frac{2 + 1 + (- 4)}{3}) = (1, 1, 0)$

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Q. A triangle has a vertex at

(1, 2)

and the mid points of the two sides through it are

(- 1, 1)

and

(2, 3)

. Then the centroid of this triangle is :

The coordinates of the mid-points of sides AB, BC and CA of $△$ are D (1, 2, -3) E(3, 0, 1) and F(-1, 1, -4) respectively. Write the coordinates of its centroid.

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Find the centroid of a triangle, mid-points of whose sides are (1,2,−3),(3,0,1) and (−1,1,−4).

A(1,2,3),B(3,0,1) and C(−1,1,−4)Centroid (G)=(1+3+(−1)3,2+0+13,2+1+(−4)3)=(1,1,0)

Find the centroid of a triangle, mid-points of whose sides are $(1, 2, - 3), (3, 0, 1)$ and $(- 1, 1, - 4)$ .

$A (1, 2, 3), B (3, 0, 1)$ and $C (- 1, 1, - 4)$
Centroid $(G) = (\frac{1 + 3 + (- 1)}{3}, \frac{2 + 0 + 1}{3}, \frac{2 + 1 + (- 4)}{3}) = (1, 1, 0)$