Question

Find the centroid of a triangle, whose vertices are $(3,4),(-7,-2)$ and $(10,-5)$.

Answer 1

Let the given vertices of a triangle be A$(3,4)$ and B $(-7,-2)$ let the third vertex be C $(10,-5)$
Let Centroid be G
centroid = [$\frac{x_1+x_2+x_3}{3}$, $\frac{y_1+y_2+y_3}{3}$]
$G$ = [ $\frac{3-7+10}{3}$ , $\frac{4-2-5}{3}]$
$G$ = $(\frac{6}{3}$ , $\frac{-3}{3})$
$G$ = $(2,-1)$
$x=2$ , $y=-1$.