Question

Find the centroid of the triangle whose vertices are A$(4,3)$, B$(0,0)$ and C $(2,3)$.

Answer 1

Given the triangle vertices are A$(4,3)$, B$(0,0)$ and C $(2,3)$.

∵ The centroid of the triangle ABC = $(\frac{x1+x2+x3}{2},\frac{y1+y2+y3}{2})$

Now, the centroid is $(\frac{4+0+2}{3},\frac{3+0+3}{3})=(2,2)$.