Question

Find the centroid of the triangle whose vertices are $(4,0),(0,-6)$ and $(2,6)$

Answer 1

Let $A(x_1,y_1)=(4,0),B(x_2,y_2)=(0,-6)$ and $C(x_3,y_3)=(2,6)$ be the points of a triangle.

$\therefore$ Centroid$G=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})$

$=(\frac{4+0+2}{3},\frac{0-6+6}{3})$

$=(\frac{6}{3},\frac{0}{3})$

$=(3,0)$

$\therefore$ Centroid is at $(3,0)$