Question

Find the centroid of $△ABC$ whose vertices are A(-3,0), B(5,-2) and C(-8,5).

Answer 1

We have,

$(x_1=-3,y_1=0),(x_2=5,y_2=-2),(x_3=-8,y_3=5)$

Let $G(x,y)$ be the centroid of $△ABC$.

We know, coordinates of centroid of triangle with vertices $(x_1,y_1),(x_2,y_2),(x_3,y_3)$ are

$(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})$

Thus,

$x=\frac{1}{3}(-3+5-8)=-2$

$y=\frac{1}{3}(0-2+5)=1$

Therefore, the centroid of $△ABC$ is $G(-2,1)$.